Question

How do you simplify `(sinx/cosx)^2-1/cos^2x`?

Answer 1

We have that

`(sinx/cosx)^2-1/cos^2x`

`sin^2x/(cos^2x)-1/(cos^2x)`

`-1/(cos^2x)*(1-sin^2x)`

`-1/(cos^2x)*cos^2x`

`-1`