How do you simplify #sinxcosxsecxcotx#?
1 Answer
Jul 7, 2018
Explanation:
#"using the "color(blue)"trigonometric identities"#
#•color(white)(x)secx=1/cosx" and "cotx=cosx/sinx#
#=cancel(sinx)xxcancel(cosx)xx1/cancel(cosx)xxcosx/cancel(sinx)#
#=cosx#
