How do you simplify #sqrt(0.25)#?

Question

5885 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-15T20:56:53

#sqrt(0.25)=+-0.5#

consider #" "5xx5=25#

Note that #0.5 -> 5/10 -> 5xx1/10#

#(color(red)(5)xxcolor(green)(1/10))xx(color(red)(5)xxcolor(green)(1/10))= color(red)(25)xxcolor(green)(1/100)= 0.25#

so #sqrt(0.25) = sqrt((5xx1/10)xx(5xx1/10) ) = 5xx1/10=0.5#

so #sqrt(0.25)=+-0.5#

Answer 2 · 2017-10-18T11:44:18

A better way of solving this

Note that #0.25# is the same as #25xx1/100#

Thus #sqrt(0.25)color(white)("dd")=color(white)("dd")sqrt(25xx1/100)color(white)("dd") =color(white)("dd") sqrt(25)/sqrt(100)#

#+-5/10=+-0.5#