Question

How do you simplify `sqrt(10a) / sqrt(12a)`?

Answer 1

This is a law

`sqrt(ab)=sqrta sqrtb`

`(sqrt(10a))/(sqrt(12a))=(sqrt5 cancelsqrt2 cancelsqrta)/(sqrt6 cancelsqrt2 cancelsqrta)`

`(sqrt(10a))/(sqrt(12a))=sqrt(5/6)`