How do you simplify #sqrt(12x+12) + sqrt(3x+3)#?

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Answer 1 · 2018-04-29T22:21:53

It simplifies to #3sqrt(3x+3)#.

Factor out a #4# on the left radical, then combine the like terms:

#color(white)=sqrt(12x+12)+sqrt(3x+3)#

#=sqrt(4(3x+3))+sqrt(3x+3)#

#=sqrt4*sqrt(3x+3)+sqrt(3x+3)#

#=2*sqrt(3x+3)+sqrt(3x+3)#

#=2sqrt(3x+3)+sqrt(3x+3)#

#=3sqrt(3x+3)#

That's it. Hope this helped!