# How do you simplify sqrt(2) / sqrt(8)?

$\frac{\sqrt{2}}{\sqrt{8}} = \frac{1}{2}$
Using the property that $\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$ for $b > 0$ we have
$\frac{\sqrt{2}}{\sqrt{8}} = \sqrt{\frac{2}{8}} = \sqrt{\frac{1}{4}} = \frac{\sqrt{1}}{\sqrt{4}} = \frac{1}{2}$