How do you simplify #sqrt(27/16)#?

2 Answers
Jul 12, 2017

Answer:

It is #(3timessqrt3)/4#

Explanation:

You can write your expression

#(sqrt27)/(4)#

since #sqrt16=4#

You can further write

#(sqrt(9times3))/4 = (3times(sqrt3))/4#

This is your answer

#(3times(sqrt3))/4#

Jul 12, 2017

Answer:

# (3sqrt3)/4#

Explanation:

Value #=sqrt(27/16)#

Expressing the numerator and denominator as their prime factors:

Value #= sqrt((3xx3xx3)/(2xx2xx2xx2))#

Taking each pair of factors once through the #sqrt#.

Value #=( 3sqrt3)/(2xx2)#

#= (3sqrt3)/4#