How do you simplify #sqrt(27/16)#?

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Answer 1 · 2017-07-12T14:20:35

It is #(3timessqrt3)/4#

You can write your expression

#(sqrt27)/(4)#

since #sqrt16=4#

You can further write

#(sqrt(9times3))/4 = (3times(sqrt3))/4#

This is your answer

#(3times(sqrt3))/4#

Answer 2 · 2017-07-12T14:26:59

# (3sqrt3)/4#

Value #=sqrt(27/16)#

Expressing the numerator and denominator as their prime factors:

Value #= sqrt((3xx3xx3)/(2xx2xx2xx2))#

Taking each pair of factors once through the #sqrt#.

Value #=( 3sqrt3)/(2xx2)#

#= (3sqrt3)/4#