How do you simplify #sqrt(3/27y^6)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Apr 13, 2015 #sqrt((3*y^6)/27)# #= sqrt((3*(y^3)^2)/(3^3))# #= sqrt(((y^3)^2)/(3^2))# In general #color(blue)(sqrt(a/b) = sqrta/sqrtb# #= sqrt((y^3)^2)/sqrt(3^2)# #color(green)( = y^3/3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1605 views around the world You can reuse this answer Creative Commons License