How do you simplify #sqrt(3/5 )#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer F. Javier B. Mar 8, 2018 #sqrt15/5# Explanation: #sqrt(3/5)=sqrt3/sqrt5=(sqrt3·sqrt5)/(sqrt5·sqrt5)=sqrt(3·5)/5=sqrt15/5# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1877 views around the world You can reuse this answer Creative Commons License