How do you simplify #sqrt 3 div 2 times sqrt 3?#?
1 Answer
Feb 14, 2016
Explanation:
note :
# sqrta xx sqrta = a# hence
# sqrt3/2 xx sqrt3/1 =( sqrt3 xx sqrt3)/(2 xx 1 ) = 3/2#
note :
# sqrta xx sqrta = a# hence
# sqrt3/2 xx sqrt3/1 =( sqrt3 xx sqrt3)/(2 xx 1 ) = 3/2#