How do you simplify #sqrt 3 times root3(3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Nityananda Jan 16, 2017 #3^(5/6)# Explanation: Given #sqrt 3 * root(3) 3# #rArr 3^(1/2) * 3^(1/3)# #rArr 3^(1/2 + 1/3)# #rArr 3^(5/6)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2864 views around the world You can reuse this answer Creative Commons License