How do you simplify sqrt(32/4)?

1 Answer
Jan 29, 2016

2sqrt2

Explanation:

There are 2 solutions :)

The first solution is:

Since sqrt(a/b) = sqrt(a)/sqrt(b), where b is not equal to 0.

First we simplify the numerator, since there is no exact value of sqrt32 we take its perfect squares. 16 is a perfect square since 4*4 = 16. Dividing 32 by 16, we get 16 * 2 = 32, therefore:

sqrt32 = sqrt16*sqrt2
= 4sqrt2

Since now we're done in the numerator, we're gonna simplify the denominator, since 4 is perfect square, 4 = 2 * 2, the sqrt4 is equal to 2.

Plugging all the answers, we get:

(4sqrt2)/2

since 4 and 2 is a whole number, we can divide these 2 whole numbers, we get:

2sqrt2

this is the final answer :)

the 2nd solution is:

First we simply evaluate the fraction inside the radical sign (square root)

sqrt(32/4) = sqrt(8)

since, 32/4 = 8, then we get sqrt8

sqrt8 = sqrt4*sqrt2

= 2sqrt2