How do you simplify #\sqrt { 36x ^ { 7} w ^ { 11} }#?

1 Answer
May 24, 2017

#6x^3w^5sqrt(xw)#

Explanation:

When dealing with square roots you are looking for squared values that you may 'take outside' the root.

Note that:
#36=6^2#
#x^7=x^2x^2x^2x =(x^2)^3x#

#w^11=(w^2)^5w#

So #sqrt(36x^7w^11)" is the same as "sqrt(6^2(x^2)^3x(w^2)^5w)#

#=6x^3w^5sqrt(xw)#