How do you simplify #(sqrt(48x^3y^2))/(sqrt4xy^3)#?
Before starting, I must say that I believe there has been a little typing mistake and that your function is
Note that as both numerator and denominator are square roots, we can then merge them in this way:
Now, let's see what composes both numerator and denominator and cancel the common elements.
Now, let's rewrite all that is left from our cancelling:
However, we still have two squared numbers (
Now, we can just rationalize this answer:
The multiplication of square roots is the square root of the multiplication. So, the final simplification is:
In case your function is just exactly as it is written here , then the same steps will follow:
Final answer, in this case, would be: