How do you simplify #sqrt(-64)/-sqrt4#?

1 Answer
Nov 5, 2015

Answer:

#sqrt(-64)/-sqrt4=-4i#

Explanation:

#[1]" "sqrt(-64)/-sqrt4#

Factor out the numbers inside the radical symbols.

#[2]" "=sqrt(-8^2)/-sqrt(2^2)#

Take the perfect squares out of the radical symbols.

#[3]" "=(8sqrt(-1))/-2#

The square root of #-1# is equivalent to the imaginary unit #i#.

#[4]" "=(8i)/-2#

Simplify by dividing #8i# by #-2#.

#[5]" "=color(blue)(-4i)#