# How do you simplify sqrt 8/ sqrt3?

##### 2 Answers
Mar 28, 2018

To answer is this: $\frac{\sqrt{8}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{8} \cdot \sqrt{3}}{3} = \frac{\sqrt{24}}{3}$

#### Explanation:

In this question, since you do not want square root functions as the divisors, you multiply the top and bottom by the square root divisor at the bottom.

In this case, $\sqrt{3}$. After multiplying the top and bottom by $\sqrt{3}$, you will remove the square root term from the bottom and as such getting you only $3$, but the top will be $\sqrt{8} \cdot \sqrt{3}$, which is $\sqrt{24}$.

In your final answer, it will then become $\frac{\sqrt{24}}{3}$.

Mar 28, 2018

$\frac{2 \sqrt{6}}{3}$

#### Explanation:

rationalise the denominator, by multiplying by $\sqrt{3} :$

$\frac{\sqrt{3} \cdot \sqrt{8}}{\sqrt{3} \cdot \sqrt{3}}$

$= \frac{\sqrt{24}}{3}$

$\sqrt{24} = \sqrt{4} \cdot \sqrt{6}$

$= 2 \cdot \sqrt{6} = 2 \sqrt{6}$

$\frac{\sqrt{24}}{3} = \frac{2 \sqrt{6}}{3}$