How do you simplify #sqrt(8y^3)-sqrt(2y^3)#?

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Answer 1 · 2015-11-22T19:45:14

#ysqrt(2y)#

#sqrt(8y^3)-sqrt(2y^3)#

Factor #sqrt{y^3}=sqrt(y^2*y)=ysqrty#

#=ysqrty*(sqrt(8)-sqrt{2})#

Simplify #\sqrt{8}=sqrt(4*2)=2sqrt2#:

#=ysqrty*(2\sqrt{2}-sqrt{2})#

#=ysqrty*sqrt{2}#

#=ysqrt{2y#