Question

How do you simplify `\sqrt { 9x ^ { 5} y ^ { 4} }`?

Answer 1

Simplifying `sqrt(9x^5y^4)` gives us `3x^2y^2` `sqrt(x)`

Explanation:

So let rewrite the problem `sqrt(9x^5y^4)`

So we have a radical but how do we get rid of the radical? Well, we can take out 3x but to what power?

So as the doorbell reads although it is assume it is a 2 unless otherwise stated. So how many group of 2 are there in 5. Well, we can take out 2 as 2 x 2 = 4. Thus giving us `3x^2` when taking it out of the house but we have to leave an x behind so it stay in the house. So far, we have this as our answer:

`3x^2` `sqrt(xy^4)`

So we can take out `y^4` out of the house and 4 is a perfect square so we can take out `y^2` which gives us our final answer of

`3x^2y^2` `sqrt(x)`