Question

How do you simplify `sqrt(sin^2xcosx)*sqrtcosx`?

Answer 1

`1/2sin2x`

Explanation:

`sqrt(sin^2xcosx)sqrtcosx`

`=sqrt(sin^2xcosxcosx)`

`=sqrt(sin^2xcos^2x)`

`=sinxcosx`

`=1/2sin2x`