How do you simplify #sqrt(t/8)#?

1 Answer
Jun 12, 2017

Answer:

#1/2sqrt(t/2)#

Explanation:

Rewrite #8# in its factors. #t# has no factors so leave it as is:

#sqrt(t/(2xx2xx2)#

Take out anything that has two of a kind. In this case, we have three #1/2#s so we can take out #2# of those. That means that we're left with #t/2# on the inside:

#1/2sqrt(t/2)#