How do you simplify #sqrt10sqrt30#?

1 Answer
Azimet
Feb 4, 2017

#10sqrt3#

Explanation:

Use the root property: #sqrtasqrtb = sqrt(ab)# and vice versa.

#sqrt10sqrt30 = sqrt300 = sqrt100sqrt3 = 10sqrt3#

You'll want to find the greatest "perfect" square factor of the number inside the root, so you can use the above property in reverse to split up the roots, then simplify. A perfect square is a square of an integer (its square root is an integer).

Related questions
See all questions in Multiplication and Division of Radicals
Impact of this question
1183 views around the world
You can reuse this answer
Creative Commons License