How do you simplify #sqrt10sqrt30#?

1 Answer
Feb 4, 2017

Answer:

#10sqrt3#

Explanation:

Use the root property: #sqrtasqrtb = sqrt(ab)# and vice versa.

#sqrt10sqrt30 = sqrt300 = sqrt100sqrt3 = 10sqrt3#

You'll want to find the greatest "perfect" square factor of the number inside the root, so you can use the above property in reverse to split up the roots, then simplify. A perfect square is a square of an integer (its square root is an integer).