How do you simplify #sqrt11 (sqrt6 - sqrt7)#?

1 Answer
EZ as pi
Aug 4, 2016

#sqrt11(sqrt6-sqrt7) = sqrt66 - sqrt77#

Explanation:

use the distributive law to multiply #sqrt11# by each of the numbers in the bracket. When we multiply square roots we can combine them into one root.

#sqrt11(sqrt6-sqrt7) = sqrt66 - sqrt77#

This cannot be simplified further without using a calculator to find the actual values.

They are irrational numbers.

Related questions
See all questions in Multiplication and Division of Radicals
Impact of this question
1045 views around the world
You can reuse this answer
Creative Commons License