How do you simplify #sqrt112-sqrt63#?

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Answer 1 · 2016-07-13T16:20:29

#sqrt7#

#sqrt112 -sqrt63#

the prime factors for each square root become

#sqrt(2*2*2*2*7) -sqrt(3*3*7)#

factor out the pairs

#2*2sqrt7 -3sqrt7#

#4sqrt7 -3sqrt7#

#sqrt7#