How do you simplify #sqrt12 + 3sqrt3#?

2 Answers
Apr 23, 2018

Answer:

#5sqrt3#

Explanation:

#sqrt12=sqrt4xxsqrt3# = #2sqrt3#

So #sqrt12+3sqrt3=2sqrt3+3sqrt3=5sqrt3#

Apr 23, 2018

Answer:

#5sqrt3#

Explanation:

#"using the "color(blue)"law of radicals"#

#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#

#3sqrt3" is in simplest form"#

#"simplifying "sqrt12#

#sqrt12=sqrt(4xx3)=sqrt4xxsqrt3=2sqrt3#

#rArrsqrt12+3sqrt3=2sqrt3+3sqrt3=5sqrt3#