How do you simplify sqrt12 times sqrt27?

Jun 23, 2016

18

Explanation:

You know that

$\sqrt{12} = \sqrt{{2}^{2} \cdot 3} = 2 \sqrt{3}$

and

$\sqrt{27} = \sqrt{{3}^{3}} = 3 \sqrt{3}$

so you can sum them:

$\sqrt{12} \cdot \sqrt{27} = 2 \sqrt{3} \cdot 3 \sqrt{3} = 6 {\sqrt{3}}^{2} = 6 \cdot 3 = 18$