How do you simplify #sqrt147+6sqrt3#?

1 Answer
Aug 27, 2016

Answer:

#sqrt(147)+6sqrt(3) = 13sqrt(3)#

Explanation:

#sqrt(147)+6sqrt(3) = sqrt(7^2*3)+6sqrt(3) = sqrt(7^2)sqrt(3)+6sqrt(3) = 7sqrt(3)+6sqrt(3) = 13sqrt(3)#

In general, when you are asked to simply anything like #sqrt(147)# start by factoring the radicand:

#147 = 3*7*7 = 3*7^2#

Since this has a square factor we can simplify its square root as shown above.