How do you simplify #sqrt16/sqrt8#?

2 Answers
Apr 26, 2018

Answer:

=#sqrt2#

Explanation:

#sqrt16/sqrt8# Multiply the fraction by #1# as #sqrt8/sqrt8#:
=#sqrt(16*8)/8# Factor #16# and #8#:
=#sqrt((2*2*2*2))*(2*2*2)# Factor out the three pairs of twos:
=#8sqrt2/8#
=#sqrt2#

OR, if you want to do it the simple way:
#sqrt16/sqrt8#
=#sqrt(16/8)#
=#sqrt2#
Sorry, forgot you could divide them xD ^^

Apr 26, 2018

Answer:

#sqrt2#

Explanation:

Simplify the square roots

#sqrt16/sqrt8# = #4/(sqrt4sqrt2)# = #4/(2sqrt2)#

Rearrange the equation so there is no square root in the denominator

#4/(2sqrt2)##sqrt2/sqrt2# = #(4sqrt2)/(2⋅2)# = #(4sqrt2)/4#

The fours cancel out and you are left with #sqrt2#