How do you simplify $\sqrt{162} - \sqrt{98}$ $sqrt162-sqrt98$ ?

Question

576 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-13T02:49:36

$2 \sqrt{2}$ $2sqrt2$

$\sqrt{162} - \sqrt{98} = \sqrt{81 \cdot 2} - \sqrt{49 \cdot 2}$ $sqrt162-sqrt98 = sqrt(81*2) -sqrt(49*2)$

= $9 \sqrt{2} - 7 \sqrt{2}$ $9sqrt2- 7sqrt2$

= $2 \sqrt{2}$ $2sqrt2$

How do you simplify sqrt162-sqrt98√162−√98sqrt162-sqrt98?