How do you simplify $\sqrt{2} \cdot \sqrt{3}$ $sqrt2 * sqrt3$ ?

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Answer 1 · 2018-04-04T03:14:56

$\sqrt{6}$ $sqrt6$

$\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b},$ $sqrt(a)*sqrt(b)=sqrt(a*b),$ so

$\sqrt{2} \cdot \sqrt{3} = \sqrt{3 \cdot 2} = \sqrt{6}$ $sqrt(2)*sqrt(3)=sqrt(3*2)=sqrt(6)$

How do you simplify √2⋅√3sqrt2 * sqrt3?