How do you simplify #sqrt28+sqrt63#?

2 Answers
Apr 23, 2018

Answer:

5#sqrt7#

Explanation:

#sqrt28# + #sqrt63#

Simplify by finding common multipliers:

#sqrt(7*2*2)# + #sqrt(7*3*3)#

Because it's a square root,2 of the same numbers can be taken from the root and put infront of the root

2#sqrt7# +3#sqrt7#

Because the square roots are the same in each number, add the coefficients

5#sqrt7#

Apr 23, 2018

Answer:

#5sqrt7#

Explanation:

#"using the "color(blue)"law of radicals"#

#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#

#sqrt28=sqrt(4xx7)=sqrt4xxsqrt7=2sqrt7#

#sqrt63=sqrt(9xx7)=sqrt9xxsqrt7=3sqrt7#

#rArrsqrt28+sqrt63=2sqrt7+3sqrt7-5sqrt7#