# How do you simplify sqrt3 (4 + sqrt12)?

$4 \sqrt{3} + 6$
$\sqrt{3} \cdot \left(4 + \sqrt{12}\right) =$
$= 4 \sqrt{3} + \sqrt{3} \cdot \sqrt{12} =$
$= 4 \sqrt{3} + \sqrt{3 \cdot 12} =$
$= 4 \sqrt{3} + \sqrt{36} =$
$= 4 \sqrt{3} + 6$