# How do you simplify sqrt3(sqrt7+3sqrt2)?

$\sqrt{21} + 3 \sqrt{6}$
$\sqrt{3} \sqrt{7} + 3 \sqrt{2} \cdot \sqrt{3} = \sqrt{21} + 3 \sqrt{6}$
$\sqrt{a} \cdot \sqrt{b} = \sqrt{a b}$ for $a , b \ge 0$