How do you simplify #sqrt300/sqrt6#?

2 Answers
Apr 19, 2018

Answer:

#(sqrt300)/(sqrt6)=sqrt50=5sqrt2#

Explanation:

#(sqrt300)/(sqrt6)#
#rArr sqrt(300/6)#
#rArr sqrt50 color(white)( "d")=sqrt(5^2xx2)#
#rArr 5sqrt2#

Apr 19, 2018

Answer:

#5sqrt2#

Explanation:

#"using the "color(blue)"law of radicals"#

#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#

#•color(white)(x)sqrta/sqrtbhArrsqrt(a/b)#

#rArrsqrt300/sqrt6#

#=sqrt(300/6)=sqrt50#

#sqrt50=sqrt(25xx2)=sqrt25xxsqrt2=5sqrt2#