# How do you simplify sqrt32 + sqrt8?

May 18, 2015

We can decouple the numbers inside the square roots:

$\sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 2} + \sqrt{2 \cdot 2 \cdot}$

As we are dealing with square roots, we can factor out all the squared numbers from inside the roots:

$\sqrt{{2}^{2} \cdot {2}^{2} \cdot 2} + \sqrt{{2}^{2} \cdot 2}$
$\sqrt{4 \cdot 4 \cdot 2} + \sqrt{4 \cdot 2}$
$\sqrt{16 \cdot 2} + \sqrt{4 \cdot 2}$
$4 \sqrt{2} + 2 \sqrt{2}$
$6 \sqrt{2}$