How do you simplify #sqrt32 + sqrt8#?

1 Answer
May 18, 2015

We can decouple the numbers inside the square roots:

#sqrt(2*2*2*2*2)+sqrt(2*2*)#

As we are dealing with square roots, we can factor out all the squared numbers from inside the roots:

#sqrt(2^2*2^2*2)+sqrt(2^2*2)#
#sqrt(4*4*2)+sqrt(4*2)#
#sqrt(16*2)+sqrt(4*2)#
#4sqrt(2)+2sqrt(2)#
#6sqrt(2)#