# How do you simplify sqrt343-sqrt252?

I found $\sqrt{7}$
$\sqrt{343} - \sqrt{252} = \sqrt{7 \cdot 49} - \sqrt{7 \cdot 36} = \sqrt{7} \sqrt{49} - \sqrt{7} \sqrt{36} = 7 \sqrt{7} - 6 \sqrt{7} = \sqrt{7}$