How do you simplify #sqrt35divsqrt7#?

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Answer 1 · 2018-06-13T07:37:36

#sqrt5#

#sqrt35 divide sqrt7#

In fraction form, you can factor out the square root (This is intuitive if you think about how #sqrtx# is the same as #x^(1/2)#)

#sqrt(35/7)#

Then dividing numerator and denominator by 7

#sqrt(5/1)# = #sqrt5#

Answer 2 · 2018-06-13T07:41:10

#sqrt5#

#"using the "color(blue)"law of exponents"#

#•color(white)(x)sqrta/sqrtbhArrsqrt(a/b)#

#sqrt35/sqrt7=sqrt(35/7)=sqrt5#