How do you simplify #sqrt5(10-4sqrt2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Jun 19, 2016 # = color(green)(10sqrt5 - 4 sqrt 10# Explanation: #sqrt5 (10 - 4sqrt2)# # = color(blue)(sqrt5) * (10 - 4sqrt2)# We multiply #color(blue)(sqrt5# with each of the two terms within brackets. # = color(blue)(sqrt5) * (10 ) + color(blue)(sqrt5) * ( - 4sqrt2)# # = 10sqrt5 + (- 4) * sqrt2 * sqrt5# # = 10sqrt5 - 4 * sqrt (2 * 5)# # = 10sqrt5 - 4 sqrt 10# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 286 views around the world You can reuse this answer Creative Commons License