How do you simplify #sqrt5/sqrt15#?

2 Answers
Apr 21, 2016

Answer:

#sqrt(3)/3#

Explanation:

Multiply a number by 1 and its inherent value does not change. Multiply by 1 but in an equivalent form and you do not change its value but you do change the way it looks.

Given:#" "sqrt(5)/sqrt(15)#

Multiply by 1 but in the form #1=sqrt(15)/sqrt(15)# giving

#(sqrt(5)sqrt(15))/(sqrt(15)sqrt(15))#

#(sqrt(5)sqrt(15))/(15)#

#sqrt(5xx15)/15#

#sqrt(5xx5xx3)/15#

#(5sqrt(3))/15#

#sqrt(3)/3#

Apr 21, 2016

Answer:

#(sqrt5)/(sqrt15)=sqrt3/3#

Explanation:

#(sqrt5)/(sqrt15)=cancel(sqrt5)/(cancel(sqrt5)*sqrt3)=1/sqrt3=sqrt3/(sqrt3*sqrt3)=sqrt3/(sqrt3)^²=sqrt3/3#