How do you simplify #sqrt6*sqrt15#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B Oct 29, 2015 #3sqrt(10)# Explanation: #6 = 3 times 2# #15=3 times 5# So we have: #sqrt(3 times 2) times sqrt(3 times 5)# #sqrt(3) times sqrt(3) times sqrt(2) times sqrt(5)# #3sqrt(10)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1519 views around the world You can reuse this answer Creative Commons License