How do you simplify #sqrt6 (sqrt3 + 5 sqrt2)#?

1 Answer
Mar 21, 2018

Answer:

#10sqrt3+3sqrt2#
You must distribute the #sqrt6#

Explanation:

Radicals can be multiplied, no matter the value under the sign.
Multiply #sqrt6*sqrt3#, which equals #sqrt18#.
#sqrt18##->##(sqrt(9*2))##->##3sqrt2# (#sqrt9=3#)
#sqrt6*5sqrt2=5sqrt12##->##5*sqrt(3*4)#
#sqrt4=2# #->## 5*2sqrt3=10sqrt3#
Hence, #10sqrt3 + 3sqrt2#