How do you simplify $\sqrt{63} - 2 \sqrt{28} + 5 \sqrt{7}$ $sqrt63-2sqrt28+5sqrt7$ ?

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Answer 1 · 2017-01-30T10:24:07

$4 \sqrt{7}$ $4sqrt7$

$\sqrt{63} - 2 \sqrt{28} + 5 \sqrt{7}$ $sqrt 63 -2sqrt28 +5sqrt7$

$\sqrt{3 \cdot 3 \cdot 7} - 2 \sqrt{2 \cdot 2 \cdot 7} + 5 \sqrt{7}$ $sqrt (3*3*7) -2sqrt(2*2*7) +5sqrt7$

$3 \sqrt{7} - 2 \cdot 2 \cdot \sqrt{7} + 5 \sqrt{7}$ $3sqrt 7 -2*2*sqrt7 +5sqrt7$

$3 \sqrt{7} - 4 \sqrt{7} + 5 \sqrt{7}$ $3sqrt 7 -4sqrt7 +5sqrt7$

$\sqrt{7} (3 - 4 + 5)$ $sqrt7(3-4+5)$

$4 \sqrt{7} 00 [Ans]$ $4sqrt7 color(white)(00)"[Ans]"$

How do you simplify sqrt63-2sqrt28+5sqrt7√63−2√28+5√7sqrt63-2sqrt28+5sqrt7?