Question

How do you simplify `sqrt63/sqrt7`?

Answer 1

`sqrt(63)/sqrt(7) = 3`

Explanation:

Using the property that `sqrt(a)/sqrt(b) = sqrt(a/b)` for `a>=0`, `b>0`:

`sqrt(63)/sqrt(7) = sqrt(63/7) = sqrt(9) = sqrt(3^2) = 3`