# How do you simplify sqrt63/sqrt7?

$\frac{\sqrt{63}}{\sqrt{7}} = 3$
Using the property that $\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$ for $a \ge 0$, $b > 0$:
$\frac{\sqrt{63}}{\sqrt{7}} = \sqrt{\frac{63}{7}} = \sqrt{9} = \sqrt{{3}^{2}} = 3$