How do you simplify $\sqrt{7} - 6 \sqrt{7}$ $sqrt7-6sqrt7$ ?

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Answer 1 · 2017-05-19T09:57:45

$- 5 \sqrt{7}$ $-5sqrt7$

Let $x = \sqrt{7}$ $x=sqrt7$

$x - 6 x = - 5 x$ $x-6x=-5x$

Substituting $\sqrt{7}$ $sqrt7$ will give us $- 5 \sqrt{7}$ $-5sqrt7$

Answer 2 · 2017-05-19T10:10:39

$- 5 \sqrt{7}$ $-5sqrt7$

Remember it is actually $1 \sqrt{7} - 6 \sqrt{7}$ $1sqrt7 -6sqrt7$

There are two terms with a common factor of $\sqrt{7}$ $sqrt7$

$1 \sqrt{7} - 6 \sqrt{7}$ $1sqrt7 -6sqrt7$

$= \sqrt{7} (1 - 6)$ $= sqrt7(1-6)$

$= - 5 \sqrt{7}$ $=-5sqrt7$

Or just treat it as adding like terms:

$1 \sqrt{7} - 6 \sqrt{7} = - 5 \sqrt{7}$ $1sqrt7 -6sqrt7 =-5sqrt7$

How do you simplify sqrt7-6sqrt7√7−6√7sqrt7-6sqrt7?