How do you simplify #(sqrt7+sqrt3)/(sqrt7-sqrt3)#?

1 Answer
Aug 29, 2016

Answer:

#(sqrt7+sqrt3)^2/4#

Explanation:

Multiply both sides by #(sqrt7+sqrt3)/(sqrt7+sqrt3)#

#(sqrt7+sqrt3)/(sqrt7-sqrt3) xx (sqrt7+sqrt3)/(sqrt7+sqrt3)#

The bottom shows the factors of the difference of squares.

#(sqrt7+sqrt3)^2/(sqrt7^2 - sqrt3^2) = (sqrt7+sqrt3)^2/(7-3)#

#(sqrt7+sqrt3)^2/4#