How do you simplify (sqrtc + d)(3 +sqrt5)?

Apr 8, 2017

(sqrtc+d)(3+sqrt5)=color(blue)(3sqrtc+sqrt5sqrtc+3d+dsqrt5

Explanation:

Simplify:

$\left(\sqrt{c} + d\right) \left(3 + \sqrt{5}\right)$

Use the FOIL method, which gives the order in which the terms of two binomials are multiplied: First, Outer, Inner, Last

$\left(\sqrt{c} + d\right) \left(3 + \sqrt{5}\right) = \left(\sqrt{c} \cdot 3\right) + \left(\sqrt{c} \cdot \sqrt{5}\right) + \left(d \cdot 3\right) + \left(d \cdot \sqrt{5}\right)$

$\left(\sqrt{c} + d\right) \left(3 + \sqrt{5}\right) = 3 \sqrt{c} + \sqrt{5} \sqrt{c} + 3 d + \mathrm{ds} q r t 5$