# How do you simplify (sqrtx+4)^2?

Apr 17, 2017

See the entire solution process below:

#### Explanation:

We can use this rule to simplify this expression:

${\left(a + b\right)}^{2} = \left(a + b\right) \left(a + b\right) = {a}^{2} + 2 a b + {b}^{2}$

Substituting $\sqrt{x}$ for $a$ and $4$ for $b$ gives:

${\left(\sqrt{x} + 4\right)}^{2} = \left(\sqrt{x} + 4\right) \left(\sqrt{x} + 4\right) = {\left(\sqrt{x}\right)}^{2} + \left(2 \sqrt{x}\right) \cdot 4 + {4}^{2}$

$= x + 8 \sqrt{x} + 16$