How do you simplify #(sqrtx+4)^2#?

1 Answer
Apr 17, 2017

Answer:

See the entire solution process below:

Explanation:

We can use this rule to simplify this expression:

#(a + b)^2 = (a + b)(a + b) = a^2 + 2ab + b^2#

Substituting #sqrt(x)# for #a# and #4# for #b# gives:

#(sqrt(x) + 4)^2 = (sqrt(x) + 4)(sqrt(x) + 4) = (sqrt(x))^2 + (2sqrt(x))*4 + 4^2#

#= x + 8sqrt(x) + 16#