How do you simplify #(sqrty-5)^2#?

2 Answers
Apr 11, 2018

Answer:

Foil and add like terms

Explanation:

I really hope that you know how to foil so I am not going to explain it but once you expand you get #(sqrty-5)(sqrty-5)#. If you did not know when you multiply two roots the cancel and the middle number stays the same. So when you foil you should get #y-5sqrty -5sqrty+25# which simplifies to #y-10sqrty+25#.

Apr 11, 2018

Answer:

#y-10sqrty+25#

Explanation:

Using the FOIL method, you can multiply the two terms inside the parenthesis together.

#(sqrty-5)^2=(sqrty-5)(sqrty-5)#

F means "first terms."

#sqrty*sqrty=sqrty^2=y#

I means "inner terms."

#-5*sqrty=-5sqrty#

O means "outer terms."

#sqrty*-5=-5sqrty#

Finally, L means "last terms."

#-5*-5=25#

Add your four results together and simplify to complete the foil.

#y+(-5sqrty)+(-5sqrty)+25#

#=y-10sqrty+25#

That is the expanded form.