How do you simplify: square root (3/ 5)?

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Answer 1 · 2015-07-26T18:58:08

Using #sqrt(a/b) = sqrt(a)/sqrt(b)# for #a >=0# and #b > 0#

#sqrt(3/5) = sqrt((3*5)/(5*5)) = sqrt(3*5)/sqrt(5*5) = sqrt(15)/5#

We could also do it the other way:

#sqrt(3/5) = sqrt(3)/sqrt(5)#

#= sqrt(3)/sqrt(5)*sqrt(5)/sqrt(5)#

#=(sqrt(3)sqrt(5))/(sqrt(5)sqrt(5))#

#=sqrt(15)/5#

using #sqrt(a)sqrt(b) = sqrt(ab)# when #a, b >= 0#