Question

How do you simplify the expression `(1-secx)/(sec^2x-1)`?

Answer 1

`=-1/(1+secx)`

Explanation:

`(1-secx)/(sec^2x-1)`

providing`" " sec^2x!=1`

`=(1-secx)/-(1-sec^2x)`

`=-cancel((1-secx))/((cancel(1-secx))(1+secx))`

`=-1/(1+secx)`