Question

How do you simplify the expression `ln(ln e)+log_2 8`?

Answer 1

You can see that from the definition of logarithm you have:
`log_ab=x -> a^x=b`

and also `log_e =ln`

So you get:

`lne=1`

`ln1=0`

`log_2(8)=3`

finally:

`ln(lne)+log_2(8)=3`